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Formula For Kinetic Theory Of Gases


Formula For Kinetic Theory Of Gases. R = 8.31 j/mol k. Pressure (p) = 1/3 [ρc 2 ] the root mean square velocity or r.m.s.

theory of gases and Expression for Pressure IIT
theory of gases and Expression for Pressure IIT from www.venkatsacademy.com

Assumptions of kinetic theory of gases. There is a negligible force of attraction between the particles of the gases. A gas consist of a very large number of molecules which are perfect elastic spheres and are identical in all respects for a given gas and are different for different gases.

How Is The Kinetic Theory Of Gases Derived?


Raising gas temperature increases kinetic energy of gas molecules and vice versa. Pressure (p) = 1/3 [ρc 2 ] the root mean square velocity or r.m.s. R is the gas constant, which is the same for all gases.

Here, K (Boltzmann Constant) = R / N


Pressure (p) = 1/3 [m/v]nc 2 and so pv = 1/3 [mnc 2 ] and this is the kinetic theory equation. According to charles’ law, the volume (v) of given mass of gas will be directly proportional to its temperature (t) at that given instant as long as the system is at constant pressure. Velocity is written as c r.m.s.

Therefore, Pv = 2Nk’t/3, This Energy Equation Calculates The Necessary Deductions Of Gas Law.


Assumptions of kinetic theory of gases. Pv = nkt n → number of molecules. There is a negligible force of attraction between the particles of the gases.

Now, Any Gas Which Follows This Equation Is Called An Ideal Gas.


So, the resultant velocity becomes: V ∝ t orv1 t1 = v2 t2 = constant. Real gases obey this equation at high pressure and low temperature

I.e., For Same P, V And T.


To derive this formula, you must equate pv = nrt with pv = 1/3nmv 2 Now the total mass of the gas m = mn, and since r = m/v we can write. Dividing by na we obtain relationship on per molecule basis 𝜖k = ek na = 3 2 r na t = 3 2 kbt kb = r∕na = 1.38064852×10−23 j/k is defined as boltzmann constant.


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